If A+B+C= 3pi /2then prove that
sin2A+ sin 2B-sin2C= -4 sinA sinB sinC
pavitarsinghharveers:
good
Answers
Answered by
0
Answer:
A+B+C= 3pi /2then prove that
sin2A+ sin 2B-sin2C= -4 sinA sinB sinC
Step-by-step explanation:
sin2A+ sin 2B-sin2C= -4 sinA sinB sinC
Similar questions