Math, asked by KillerYash001, 1 year ago

If (a+b-c)-4, (ab-bc-ca)=1, find the value of a2+ba+c2.

Answers

Answered by gautam2406

1

Step-by-step explanation:

a^2+b^2+c^2=(a+b+c)^2-2(ab+bc+ca)=4^2-2×1=16-1=15

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