Math, asked by kalidassbhasi3, 1 year ago

if a+b+c=4 and (a+b+c) whole square = 14, then what is ab+bc+ca

Answers

Answered by mysticd
1
i think the problem is like this
a+b+c=4----(1)
a^2+b^2+c^2=14-------(2)

a^2+b^2+c^2+2(ab+bc+ca)=(a+b+c)^2

14+2(ab+bc+ca)=4^2

2(ab+bc+ca)=16-14

ab+bc+ca=2/2

ab+bc+ca=1

mysticd: thank you
Answered by 1RADHIKAA1
3
given that a+b+c     = 4
                 (a+b+c)² =14

a^2+b^2+c^2+2(ab+bc+ca)=(a+b+c)^2
14+2(ab+bc+ca)=4^2
2(ab+bc+ca)=16-14
ab+bc+ca=2/2

ab+bc+ca=1
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