if a+b+c=4 and ab+bc+ca=12 them find the value of a²+b²+c²
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Step-by-step explanation:
Given that,
a+ b + c = 4 and ab + bc + ca = 12
∴ a² + b² + c² = ( a + b + c )² - 2 ( ab + bc + ca )
= ( 4 )² - 2 ( 12 )
= 16 - 24
= - 8 is the answer.
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