If A + B + C = 45°, the find the value of /sigma(tanA + tanB + tanC).
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Answered by
3
It's tan 45 = 1
As A + B + C = 45
Let A=B=C=X
then 3 X = 45
X is 15
(Tan 15 ) 3 = tan 45 which is 1
As A + B + C = 45
Let A=B=C=X
then 3 X = 45
X is 15
(Tan 15 ) 3 = tan 45 which is 1
Saiveeksh999:
Hopes this is helps u @ Hardiksharma
Answered by
18
Answer:
1 + pi tanA
or
1 + tanA tanB tanC
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