if a+b+c=5.ab+bc+ca=7,abc=3 find the value of (a/b+b/a)+(b/c+c/b)+(c/a+a/c)
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Answered by
8
Answer:
We have,
a+b+c=5
ab+bc+ca=10
Since,
(a+b+c)
2
=25
a
2
+b
2
+c
2
+2(ab+bc+ca)=25
a
2
+b
2
+c
2
+2×10=25
a
2
+b
2
+c
2
=5
We know that,
a
3
+b
3
+c
3
−3abc=(a+b+c)(a
2
+b
2
+c
2
−(ab+bc+ca))
a
3
+b
3
+c
3
−3abc=(5)×(5−10)
a
3
+b
3
+c
3
−3abc=5×−5
a
3
+b
3
+c
3
−3abc=−25
Step-by-step explanation:
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Answered by
4
Answer:
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