Question

If a+b+c=5, ab+bc+ca=8 and abc= (-7) then find the value of,
(a^2/b+ b^2/a)+ (b^2/c+c^2/b)+ (c^2/a+a^2/c)

Answer 1

Answer:

a+b+c=5    a2+b2+c2=29

(a+b+c)2=a2+b2+c2+2ab+2bc+2ca

25=29+2(ab+ac+bc)

2(ab+bc+ac)=−4

ab+bc+ac=−2