Question

If a + b + c= 5, and ab + bc + ca = 10, then find the value of a³ + b³ + c³ -3abc

Answer 1

a+b+c=5

S.B.S on both side

(a+b+c)²=(5)²

a²+b²+c²+2ab+2bc+2ac=25

a²+b²+c²+2(10)=25

a²+b²+c²+20=25

a²+b²+c²=25-20

a²+b²+c²=5

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ac)

= (5) {5-(10)

= 5×-5

= -25

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