Question

If a+b+c=5 and ab +bc + ca =10, then find the value of a3+b3+c3 - 3 abc​

Answer 1

Answer:

-25

Step-by-step explanation:

a+b+c =5

ab+bc+ca=10

(a+b+c)²= 25. ( squaring both side)

a²+b²+c²+2(ab+bc+ca)=25

a²+b²+c²+2×10=25

a²+b²+c²=25-20

a²+b²+c²=5

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-(ab+bc+ca)

=5×(5-10)

=5×-5

= -25

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