If a+b+c=5 and ab + bc + ca=10, then prove that a^3 + b^3 + c^3-3abc=
a)25
b)- 25
c)52
d)-52
Answers
Answered by
2
Answer:
remember the formula and put the values
hope you understand
keep studying
have nice day
Attachments:
Answered by
2
a^3 + b^3 + c^3 - 3abc = (a+b+c)(a2 + b2 + c2 + ab + bc + ca)
(a+b+c)^2 = [a2 + b2 + c2 + 2(ab + bc + ca)]
(5)^2 = a2 + b2 + c2 + 2(10)
25 = a2 + b2 + c2 + 20
25 - 20 = a2 + b2 + c2
a2 + b2 + c2 =5
a^3 + b^3 + c^3 - 3abc = (5)(5+10)
a^3 + b^3 + c^3 - 3abc = 5(15) = 75
Hope it helps please mark as brainliest
(a+b+c)^2 = [a2 + b2 + c2 + 2(ab + bc + ca)]
(5)^2 = a2 + b2 + c2 + 2(10)
25 = a2 + b2 + c2 + 20
25 - 20 = a2 + b2 + c2
a2 + b2 + c2 =5
a^3 + b^3 + c^3 - 3abc = (5)(5+10)
a^3 + b^3 + c^3 - 3abc = 5(15) = 75
Hope it helps please mark as brainliest
Similar questions