Question

If a + b + c = 5 and ab + bc + ca = 10, then prove that a

3+ b3+ c3–3abc = – 25.​

Answer 1

Answer:

-25

Step-by-step explanation:

a²+b²+c²=(a+b+c)²-2(ab+bc+ca)

=25-2(10)

=25-20

=5

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

=(5)(5-10)

=5(-5)

=-25.

Answer 2

Answer:

hi!

here is your answer!

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)

(5)²=a²+b²+c²+2(10)

25=a²+b²+c²+20

a²+b²+c²=5

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

=(5)(5-10)

=(5)(-5)

=-25

hence proved !

hope it helps you!

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