Question

If a+b+c=5 and ab+bc+ca=15,then find the value of (a+b)^3+(b+c)^3+(a+c)^-3(a+b)(b+c)(c+a)

Answer 1

Step-by-step explanation:

(a +b)3 + (b +c)3 + (c + a)3 - 3(a + b(b +cc

+a) 2a3+ 2b3 +2c3 6abc

2a3+2b3+2c3- 6abc 2(a3+ b3 +c3 -

3abc) 2(a + b+ c(a2 + b2 +c2 - (ab tbc +

()

ca)

-=-.

(a +b +c)2 = a2 +b2 +c2 +2(ab +bc + ca)

52 a2 +b2 + c2 + 30

25-30= a2 + b2+ c2

- 5 a2 +b2 + c2

Putting the values in equation (i) we get

2(5 -5 - 15)

2(5-20) = - 200

Ans: 200

Therefore you can conclude to this point

that it must be a property that

2a3+2b3+2c3 6abc 2(a3+b3 +c3 -

3abc)= 2(a +bt c)(a2 + b2 +c2 - ab - bc -

ca

hope it helps

Answer 2

Answer:

200

Step-by-step explanation:

I do my best.

thank you ~♥~