if A +B+C=5and AB+BC++AC=10 find the value of a qube + +b qube +c qube _3 abc
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(5)²=a²+b²+c²+2(10)
25=a²+b²+c²+20
a²+b²+c²=5
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
=(5)(5-10)
=(5)(-5)
=-25
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