Question

If a+b+c=6,a^2+b^2+c^2=12, find a^3+b^3+c^3-3abc

Answer 1

Answer is 144. Hope it helps you.

Answer 2

Answer:

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Step-by-step explanation:

A+b+c= 6 and a 2 + b 2 +c 2 = 12, find the value of a 3 +b 3 +c 3 -3abc  

Consider the formula - a³+b³+c³- 3abc = (a+b+c) (a²+b²+c²-(ab+bc+ca))

We have to find ab+bc+ca

given a+b+c = 6

Squaring on both sides we get,

(a+b+c)² = 6²

a²+b²+c² + 2(ab+bc+ca) = 36

2 (ab+bc+ca) = 24

ab + bc + ca = 12

Now, a³+b³+c³-3abc = (a+b+c) (a²+b²+c²-(ab+bc+ca))

Putting the values we get

6 (12 - 12)

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