if a + b + c = 6, a square + b square + c square = 12 find a cube plus b cube plus c cube -
3 ABC
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Answered by
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a=2
b=2
c=2
so,a^3+b^3+c^3-3abc=2^3+2^3+2^3-3*2*2*2
=8+8+8-3*8
=24-24
=0
b=2
c=2
so,a^3+b^3+c^3-3abc=2^3+2^3+2^3-3*2*2*2
=8+8+8-3*8
=24-24
=0
Answered by
0
buddy here is your answer and hope it helps you
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