Math, asked by pinkynabehera19, 1 year ago

If A+B+C = 6, A X B = 2, B X C = 6, then C X A = ?


siddhartharao77: Given A + B + C = 6, A X B = 2 and B X C = 6

Keep These in equations.

A X B = 2 can be written as A = 2/B ---- i

B X C = 6 can be written as C = 6/B ---- ii

Substituting i and ii in A + B + C = 6 i.e

2/B + B + 6/B =6

(2 + B^2 + 6)/B = 6

B^2 + 8 = 6B

B^2 – 6B + 8 = 0

(B – 4) (B – 2) = 0

B = 2 or 4

Assume B as 2

A = 2/2 = 1

C = 6/2 = 3

So,

C x A = 3 x 1 = 3.

Answers

Answered by Avani3
1
A=1, B=2,C=3
THEN A*B=2 
B*C=6
C*A=3

Answered by Sunny1397
0
 A+B+C=6
A*B=2
B*C=6
C*A=3

Similar questions