Question

if a+b+c=6 ,ab+bc+ca=3 find a³+b³+c³-3abc​

Answer 1

Answer:

a³ + b³ + c³ -3abc = ( a + b + c)(a² + b² + c² - ab - bc - ca)

a³ + b³ + c³ -3abc = 6*3=. 18

Answer 2

Answer:162

Step-by-step explanation:

a³+b³+c³-3abc = a+b+c [(a+b+c)²-3(ab+bc+ca)

a³+b³+c³-3abc= 6[(6)²-3×3]

a³+b³+c³-3abc= 6(36-9)

a³+b³+c³-3abc=6×27

a³+b³+c³-3abc=162