Question

if a+b+c=6,abc=6 and ab+bc+ca=11. then find a3+b3+c3​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given a + b + c = 6 and ab + bc + ca = 11

(a + b + c)2 = a2 + b2 +c2 +2(ab + bc + ca)

(6)2 = a2 + b2 +c2 + 2 x 11

a2 + b2 +c2 = 36 – 22 = 14

a3 +b3 +c3 − 3abc = ( a + b + c)[ a2 + b2 +c2 −(ab + bc + ca)]

= 6 x (14 - 11)

= 6 × 3

= 18

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