Question

if a+b +c =6 and a^2+b^2+c^2=14 then the value of (a-b) ^2 +(b-c) ^2+(c-a)^2​

Answer 1

Answer:

11

Step-by-step explanation:

we know that : (a+b+c)^2 = a^2+b^2+c^2 + (ab+bc+ca)

\

= 6^2= 14+2(ab+bc+ca)

/

\

= (36-14)/2 =(ab+bc+ca)

/

\

= ab+bc+ca = 11

/