Question

if a+b+c=6 and a²+b²+c²=20 find an+bc+ca ​

Answer 1

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Answer 2

Answer:

Hi friend here is your answer....

• Given : a+b+c=6

$a^{2} +b^{2} +c^{2} = 20$.......eq1

too find : ab+bc+ca= ?

Step-by-step explanation:

$a^{2} +b^{2} +c^{2} = 20$.

so..we take square as common..

$(a+b+c)^{2} =20$

36-2(ab+bc+ca)=20

-2(ab+bc+ca)=20-36

ab+bc+ca=-16/-2

ab+bc+ca=8

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