Question

if a+b+c =6 and a2+b2+c2=38 find a(b2+c2)+b(c2+a2)+c(a2+b2)+3abc​

Answer 1

Answer:

can't understand anything

Answer 2

Answer:

Step-by-step explanation:

a + b + c = 8

Doing square both side

(a + b + c)² = 64

a² + b² + c² + 2(ab + bc + ca) = 64

30 + 2(ab + bc + ca) = 64

2(ab + bc + ca) = 34

ab + bc + ca = 17