Question

If a + b + c = 6 and a² + b² + c² = 60, then find ab + bc + ca and a³ + b³ + c³ - 3abc.

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

a+b+c=6 square both side

a^2+b^2 +c^2 +2(ab+bc+ca)=36

60+2(..)=36

ab+bc+ca = - 12

Now, a^3 +b^3+c^3= (a+b+c) (a^2 +b^2 +c^2-ab-bc-ca) +3abc

Then a^3 +b^3+c^3 - 3abc = 6×(60+12)

= 6×72

=432

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