Question

If a+b+c=6 and ab+bc+ca= 10 then the value of a³+b³+c³-3abc is

Answer 1

(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

(a+b+c)^2=6^2

a^2+b^2+c^2=36-20

=16

Then (6)(16-10)

(6)(6)

36