If a+b+c=6 and ab+bc+ca=11 find a^2+b^2+c^2
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this is correct answer
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Step-by-step explanation:
We know that (a+b+c)²= a²+b²+c²+2(ab+bc+ca)
=>a²+b²+c²= (a+b+c)²- 2(ab+bc+ca)
= a²+b²+c²= 6²-2×11
a²+b²+c²=36-22
a²+b²+c²= 14
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