Math, asked by Rinaax7539, 8 months ago

If a+b+c=6 and ab+bc+ca =11 find a³+b³+c ³- 3abc

Answers

Answered by parth0020

0

Answer:

We know that

a+b+c+ab+bc+ca =a3+b3+c3-3abc

6+11=a3+b3+c3-3abc

Therefore a3+b3+c3-3abc= 17

Please mark my answer as the brainliest..

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