Question

If a+b+c=6 and ab+bc+ca=11, find a3+ b3+ c3- 3abc​

Answer 1

Answer:

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Step-by-step explanation:

Given a+b+c = 6 , ab + bc + ca = 11

( a + b + c )² = a² + b² + c² + 2 (ab + bc + ca)

⇒ (6)² = a² + b² + c² + 2(11) ⇒ a² + b² + c² = 36-22 = 14

now a³ + b³ + c³ -3abc= ( a + b + c) (a² + b² + c² - ab - bc - ca )

⇒ (6)(14 - 11) = 6. 3 = 18

hope u'll get my ans............

Answer 2

The answer is 18......