Question

If a+b+c=6 and ab+bc+ca=11,find the value of a^3+b^3+c^3-3abc​

Answer 1

Answer:

18

Step-by-step explanation:

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Answer 2

Answer:

Given  a+b+c = 6 ,  ab + bc + ca = 11

(a + b + c)² = a² + b² + c² + 2 (ab + bc + ca)

⇒(6)² = a² + b² + c² + 2(11) ⇒ a² + b² + c² = 36-22 = 14.

Now, a³ + b³ + c³ -3abc =  (a + b + c) (a² + b² + c² - ab - bc - ca )

⇒ (6)(14 - 11) = 6 × 3 = 18.

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