Question

If a + b +c = 6 and ab + bc+ ca = 11, find the value of a³ + b³ + c³ - 3abc.

Answer 1

$\huge\bold{\blue{\fbox{SOLUTION}}}$

a + b + c = 6 and ab + bc + ca = 11

Let a = 3

b = 1 and

c = 2

Now, putting the values in the given equations.

a + b + c = 6 and ab + bc + ca = 11

3 + 1 + 2 = 6 and 3 * 1 + 1 * 2 + 3 * 2 = 11

3 + 2 + 6 = 11. 11 = 11

Now, put the values in the equation we have to find that is

= a^2 + b^2 + c^c - 3abc

= 3^2 + 1^2 + 2^2 – 3*3*1*2

= 9 + 1 + 4 – 18

= 14 – 18

= - 4.

Hence, the answer is -4.