Math, asked by ckr59656, 2 months ago

If a +b+c=6 and ab+bc+ca=15, then a² +
 {b}^{2}  + c {}^{2}






Answers

Answered by joelpaulabraham
0

Answer:

a² + b² + c² = 6

Step-by-step explanation:

We have,

a + b + c = 6

ab + bc + ac = 15

Now, we know that,

To get a² + b² + c²,

we must definitely square our equation.

Then,

a + b + c = 6

Squaring both sides,

(a + b + c)² = 6²

a² + b² + c² + 2(ab + bc + ac) = 36

Putting in the values of what is given,

a² + b² + c² + 2(15) = 36

a² + b² + c² + 30 = 36

a² + b² + c² = 36 - 30

a² + b² + c² = 6

Hence,

a² + b² + c² = 6

Hope it helped and believing you understood it....All the best

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