if a+b+c=6 and ab+bc+ca=15, thena^+b^+c^=
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Answer:
a² + b² + c² = 6
Step-by-step explanation:
We know that,
(a²+b²+c²)² = a² + b² + c² + 2ab +2bc +2ca
=> a² + b² + c² + 2(ab + bc + ca)
So, (6)² = a² + b² + c² + 2(15)
a² + b² + c² = 36 - 30 = 6
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