Question

If a+b+c=6 and abc=6 and 1/a+1/b+1/c= 11/6 then find the value of a, b and c​

Answer 1

Answer:

66

Step-by-step explanation:

bc(b+c)+ca(c+a)+ab(a+b)+3abc

b ² c+c²b+c²a+a²b+b²a+abc+abc

bc(a+b+c)+ac(a+b+c)+ab(a+b+c)

=(a+b+c)(ab+bc+ac)=6×11=6

Alternate Method : If a=1,b=2 and c=3 then,

bc(b+c)+ca(c+a)+ab(a+b)+3abc

=6×5+3×4+2×3+3×6=30+12+6+18=66.

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