If a+b+c=6, find the value of (2-a)^3+(2-b)^3+(2-c)^3-3 (2-a)(2-b)(2-c)
Answers
Answered by
3
Answer:
Step-by-step explanation:
Attachments:
aleena0102:
thank you so much.....brother....
I have a doubt.....
how did 1/2 come?
this is according to the formula
x^3 + y^3 + z^3 - 3xyz = (1 / 2)(x + y + z)[(x - y)^2 + (y - z)^2 + (z - x)^2]
now choose x = 2 - a, y = 2 - b, z = 2 - c
ok
thanks
Similar questions