Math, asked by sonumangotra4211, 1 year ago

If a+b+c=6 find the value of (2-a)^3+(2-b)^3+(2-c)^3-3(2-a)(2-b)(2-c)

Answers

Answered by paragnimjevsnp42rxx
0

Answer:

Step-by-step explanation:

a+b+c=6

a=6-b-c

b=6-a-c

c=6-a-b

Put all this value in the given equation

(a-b)³=a³+b³-3a²b-3ab²

Use these identity

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