If a+b+c=6 find the value of (2-a)^3+(2-b)^3+(2-c)^3-3(2-a)(2-b)(2-c)
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Answer:
Step-by-step explanation:
a+b+c=6
a=6-b-c
b=6-a-c
c=6-a-b
Put all this value in the given equation
(a-b)³=a³+b³-3a²b-3ab²
Use these identity
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