Question

if a+b+c=6, then find the value of (2 - a ) ^3 + ( 2 - b ) ^3 + ( 2 - c ) ^3 - 3 (2 - a ) (2 - b) (2 - c). please don't solve if you dont know

Answer 1

Heya

Sorry I don't know :v:

Or perhaps, we do know that if :
$x + y + z = 0$

Then,
${x}^{ 3} + {y}^{3} + {z}^{3} - 3xyz = 0$

Now,

$a + b + c = 6$

$= > (2 - a) + (2 - b) + (2 - c) = 0$

$= > {(2 - a)}^{3} + {(2 - b)}^{3} +{(2 - c)}^{3} - 3(2 - a)(2 - b)(2 - c) = 0$

Hence, the required value = 0