if a + b + c = 6 then the value of 2 minus a cube + 2 minus b cube + 2 minus c cube minus 3 whole 2 - a + 2 - b 2 - C is
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a+b+c = 6
means 2-a + 2-b + 2-c = 0
let 2-a be x
2-b be y
2- c be z
what we need to find is x³+y³+z³-3xyz which equals to (x+y+z)(x²+y²+z²-xy-yz-zx)
but we know that x+y+z is 0
hence the answer is zero
means 2-a + 2-b + 2-c = 0
let 2-a be x
2-b be y
2- c be z
what we need to find is x³+y³+z³-3xyz which equals to (x+y+z)(x²+y²+z²-xy-yz-zx)
but we know that x+y+z is 0
hence the answer is zero
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