if a+b+c=6 then value of a3 +b3+c3-3abc
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0
Answer:
-4
Step-by-step explanation:
Solution:-
a+b+c=6 and ab+bc+ca=11
Let a =3
b=1 and
c=2
Now, putting the values in the given equations.
a+b+c=6 and ab+bc+ca=11
3+1+2=6 and 3*1+1*2+3*2=11
3+2+6=11. 11=11
Now, put the values in the equation we have to find that is
a^2+b^2+c^c-3abc
3^2+1^2+2^2–3*3*1*2
9+1+4–18
14–18
-4.
Hence, the answer is -4..
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