If a+b+c=6and a²+b²+c²=20,find ab+bc+ca
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Answered by
1
Answer:
a+b+C =6
squaring both side
a2+ b2+ c2+ 2(ab+bc+ca) = 36
as we know from question
20+ 2(ab+bc+ca) = 36
2(ab+bc+ca)= 16
ab+bc+ca= 8
Answered by
2
(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
6^2=20+2(ab+bc+ca)
36-20=2(ab+bc+ca)
16/2=ab+bc+ca
ab+bc+ca=8......
Hope it helps.....
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