If a+b+c=7 and a2+b2+32=45 find the value of ab+bc+ca
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Answer:
ab +bc +ca = 2
Step-by-step explanation:
a + b + c = 7
a² + b² + c² = 45
a + b + c = 7
(a+b+c)² = 7²
a² + b² + c² +2ab +2bc +2ca = 49
45 + 2(ab +bc +ca) = 49
2(ab +bc +ca) = 49 -45
ab +bc +ca = 4/2
ab +bc +ca = 2
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