Question

If (a + b + c) = 7 and (ab + bc + ac) = 19, the value of (a²+b²+c²) =

(a)49 (b) 38 (c)11 (d)26​

Answer 1

Answer:

Option c =11

Step-by-step explanation:

(a+b+c)^2= a^2+b^2+c^2+2(ab+bc+ac)

(7)^2=a^2+b^2+c^2+2(19)

49=a^2+b^2+c^2+38

a^2+b^2+c^2=49-38

a^2+b^2+c^2=11

therefore option c is correct i.e 11

hope it helps

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Answer 2

$\sf {a}^{2} + {b}^{2} + {c}^{2} = 11$