If a+b+c=7 and ab+bc+ca=20,then find the value of a^2+b^2+ c^2.
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Answered by
4
(a + b + c)² = a² + b² + c² + 2 (ab + bc + ca)
(7)² = a² + b² + c² + 2 (20) ⇒ a² + b² + c² = 49 - 40 = 9
hope this helps
(7)² = a² + b² + c² + 2 (20) ⇒ a² + b² + c² = 49 - 40 = 9
hope this helps
Answered by
7
(a+b+c)^2= (a^2+b^2+c^2) +2ab + bc+ca
(7)^2 = a^2+b^2+c^2+ 2(ab+bc+ca)
49 = a^2+b^2+c^2 +2(20)
49-40=9 = a^2+b^2+c^2
I hope that it's right
(7)^2 = a^2+b^2+c^2+ 2(ab+bc+ca)
49 = a^2+b^2+c^2 +2(20)
49-40=9 = a^2+b^2+c^2
I hope that it's right
prerna16:
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