if a + b + c = 7 and ab + bc +ca = 21 then find the value of a^2 + b^2 + c^2
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Answered by
15
Answer:
7
Step-by-step explanation:
Given,
a + b + c = 7
ab + bc + ca = 21
To find : a^2 + b^2 + c^2 = ?
( a + b + c )^2 = a^2 + b^2 + c^2 + 2 ( ab + bc + ca )
7^2 = a^2 + b^2 + c^2 + 2 ( 21 )
49 = a^2 + b^2 + c^2 + 42
a^2 + b^2 + c^2 = 49 - 42
a^2 + b^2 + c^2 = 7
harshtiwari23:
that was quick
Thank you
But, this question is very easy.
i was just cross checking
Ohk
what is the probability of possible event?
is it 1/1
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