if a+b+ c = 7 and ab+ bc+ ca= 2a find the
value of a^2 + b^2 + c^2
use (a+b+c) ² = a² + b² + c² + [2 (ab + bc + ca]
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Solution :-
Given ,
- a + b + c = 7
- ab + bc + ac = 2a
- Hint :- ( a + b + c )² = a² + b² + c² [ 2 ( ab + bc + ac ) ]
We need to find ,
- a² + b² + c²
By using the given hint ,
• ( a + b + c )² = a² + b² + c² + [ 2 ( ab + bc + ac ) ]
Substituting the given values
⇒ ( 7 ) ² = a² + b² + c² + [ 2 ( 2a ) ]
⇒ 7² = a² + b² + c² + [ 4a ]
⇒ 49 = a² + b² + c² + 4a
⇒ 49 - 4a = a² + b² + c²
[ °.° 4 transposed to RHS ]
⇒ a² + b² + c² = 49 - 4a
Hence , a² + b² + c² = 49 - 4a
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