If (a + b + c) = 8 and (a² + b² + c²) = 30 then (a³ + b³ + c³ - 3abc) = ?
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(a³-b³-c³-3abc)
=(a+b+c)(a²+b²+c²-ab-bc-ca)
=8[30-{(a²+b²+c²)-(a+b+c)²}÷2]
=8(30-23)
=56
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