Question

If (a + b + c) = 8 and (a² + b² + c²) = 30 then (a³ + b³ + c³ - 3abc) = ? ​

Answer 1

Answer:

your answer attached in the photo

Answer 2

(a³-b³-c³-3abc)

=(a+b+c)(a²+b²+c²-ab-bc-ca)

=8[30-{(a²+b²+c²)-(a+b+c)²}÷2]

=8(30-23)

=56