Question

if (a+b+c) =8 and (ab+bc+CA) = 19 , find (A2+B2+c2).

Answer 1

now(a+b+c)^2=a^2+b^2+c^2+2(ab+bc +ca)
thus, (8)^2=a^2+b^2+c^2+2*19
a^2+b^2+c^2=64-38=26

Answer 2

${(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca) \\ {8}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2 \times 19 \\ {a}^{2} + {b}^{2} + {c}^{2} = 64 - 38 = 26$
I hope I solved your problem mark me as brainly