Question

If a + b + c = 8 and ab + bc + ca = 19, then find a2+b2+c2

Answer 1

this may help u . this is the easiest method known by me

Answer 2

Answer:

$a^{2}+b^{2}+c^{2}=26$

Step-by-step explanation:

$Given\:a+b+c=8\:--(1)\\ab+bc+ca=19\:---(2)$

/*By algebraic identity:

a²+b²+c² = (a+b+c)²-2(ab+bc+ca)

= 8²-2×19 [From (1) & (2)]

= 64 - 38

= 26

Therefore,

$a^{2}+b^{2}+c^{2}=26$

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