if a+b+c=9,ab+bc+ca=26,find the value of a²+b²+c².
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given,
a+b+C =9
on squaring both the sides,
(a+b+C)^2 = 9^2
a^2 + b,^2+c^2+2ab+2bc+2ca=81
a^2+b^2+c^2+2(ab + bc+ ca) = 81
a^2+b^2+c^2 +(2×26)=81
a^2+b^2c^2= 81-52
a^2+b^2+c^2= 29
I hope it is correct
plz mark as a brainliest
a+b+C =9
on squaring both the sides,
(a+b+C)^2 = 9^2
a^2 + b,^2+c^2+2ab+2bc+2ca=81
a^2+b^2+c^2+2(ab + bc+ ca) = 81
a^2+b^2+c^2 +(2×26)=81
a^2+b^2c^2= 81-52
a^2+b^2+c^2= 29
I hope it is correct
plz mark as a brainliest
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