Math, asked by Namjoonie7, 19 hours ago

If a+b+c=9, ab+bc+ca=26, find the value of a²+b²+c².​

Answers

Answered by akashmishra12337
1

Step-by-step explanation:

a+b+c=9

squaring both side

(a+b+c)^2=(9)^2

a^2 +b^2+c^2 +2( ab +bc+ ca) = 81

a^2 +b^2+c^2+2(26)= 81

a^2 +b^2+c^2+ 52= 81

a^2 +b^2+c^2= 81 - 52

a^2 +b^2+c^2= 29

Answered by XxDKsallaccxX
1

Answer:

Deoxyribonucleic Acid for ur Frist question

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