If a+b+c=9, ab+bc+ca=26, then find a²+b²+c²
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(a+b+ c) = 9 and (ab + bc + ca) = 26 (a + b + c)2 = 92 ⇒ a2 + b2 + c2 + 2(ab + bc + ca) = 81 ⇒ a2 + b2 + c2 + 2(26) = 81 ⇒ a2 + b2 + c2 + 52 = 81 ⇒ a2 + b2 + c2 = 81 − 52 = 29
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