if a+b+c=9 and a^2+b^2=c^2=35,find the value of a^3+b^3+c^3-3abc pls do it fast.....it is very important......
Answers
Answered by
2
Answer:
108
Step-by-step explanation:
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
(9)²=35+2(ab+bc+ca)
81-35=2(ab+bc+ca)
46/2=(ab+bc+ca)
ab+bc+ca=23
a³+b³+c³-3abc=(a+b+c)[a²+b²+c²-(ab+bc+ca)]
=(9)[35-(23)]
=9×(12)
=108
Similar questions