If a+b+c=9 and a²+b²+c²=35 find value of a²+b²+c²-3abc
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Step-by-step explanation:
given-
a+b+c = 9. .......…..............(1)
a^2+b^2+c^2 = 35...........(2)
Squaring both the sides in (1)
(a+b+c)^2 = 9^2
a^2+b^2+c^2+2(ab+bc+ca) = 81
35+2(ab+bc+ca) = 81 (from 2)
2(ab+bc+ca) = 81-35
2(ab+bc+ca) = 46
ab+bc+ca = 46/2
ab+bc+ca = 23....................(3)
a^3+b^3+c^3-3abc =
(a+b+c)(a^2+b^2+c^2-ab-bc-ca)
(9)(35-23) (from 1, 2 and 3)
9*12
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